(4,5 - 2,3 -2,1) Х = 4, 5 - 4,6
0,1Х = - 0,1
Х = 1
1) <span>9x^3-18x^2-x+2=0</span>
9x^3-18x^2-x+2 / x-2
9x^3-18x^2 9x^2-1
-x+2
-x+2
0
(9x^2-1)(x-2)=0
9x^2-1=0 x-2=0
x^2=1/9 x=2
x=+-1/3
Ответ: -1/3;1/3;2.
1)(7x+10)(10y-7x)=70xy -49x^2+100^2-70xy=-49x^2+100y^2.
2)(3a-0,2b)^2=9a^2-1,2ab+0,4b^2.
3)(0,1x+2y)^2=0,01x^2+0,4xy+4y^2.
4)(a-1)(a^2+a+1)=a^3+a^2+a-a^2-a-1=a^3-1.
5)(y+2)(y^2-2y+4)=y^3-2y^2+4y+2y^2-4y+8=y^3+8.
8Sin²(π/8 -2x) - Cos²(π/8 -2x) = 1/2Sin(4x -π/4)
8Sin²(π/8 -2x) - (1 - Sin²(π/8 -2x)) = 1/2Sin(4x -π/4)
Sin²(π/8 -2x) +7Sin²(π/8 -2x) - (1 - Sin²(π/8 -2x)) = 1/2Sin(4x -π/4)
Sin²(π/8 -2x) +7Sin²(π/8 -2x) - 1 + Sin²(π/8 -2x) = 1/2Sin(4x -π/4)
7Sin²(π/8 -2x) = 1/2*2Sin(2x -π/8)Cos(2x -π/8)
7Sin²(π/8 -2x) = Sin(2x -π/8)Cos(2x -π/8)
7Sin²(π/8 -2x) - Sin(2x -π/8)Cos(2x -π/8) = 0
7Sin²(π/8 -2x) + Sin(π/8 -2x)Cos(2x -π/8) =0
Sin(π/8 -2x)(7Sin(π/8 -2x + Cos(π/8 -2x)) = 0
Sin(π/8 -2x) = 0 или 7Sin(π/8 -2x + Cos(π/8 -2x)= 0 | : Cos(π/8 -2x)≠0
π/8 -2x = πn, n∈Z 7tg(π/8 -2x) +1 = 0
2x = π/8 - πn , n∈Z tg(π/8 -2x) = -1/7
x = π/16 -πn/2, n ∈Z π/8 -2x = arctg(-1/7) + πk , k ∈ Z
x = π/16 +2arctg(1/7) -2πk , k ∈Z