Question

Решите Пожалуйста!!!!!!!!!!!!!!

Answer 1

$1) 2^{-3}*2^4=2^{-3+4}=2^1=2$
$2)27*3^{-4}=3^3*3^{-4}=3^{3-4}=3^{-1}= \frac{1}{3}$
$3)81^{3}:(9^{-2})^{-3}=(3^4)^3:((3^2)^{-2})^{-3}=3^{4*3}:3^{2*(-2)*(-3)}=3^{12}:3^{12}$$=3^{12-12}=3^0=1$

Answer 2

2⁻³ * 2⁴= 2⁻³⁺⁴ = 2¹ =2
27 *3⁻⁴ = 3³ * 3⁻⁴ = 3³⁻⁴ = 3⁻¹ = 1/3
81³ : (9⁻²)⁻³ = (9²)³ : 9⁶= 9⁶ :9⁶ = 9° =1