Запишем сумму геометрической прогресси
S3=b1(1-q^3)/(1-q)
S6=b1(1-q^6)/(1-q)
S3/S6=(1-q^3)/(1-q^6)=28
1-q^3=28-28q^6
28q^6-q^3-27=0
q=1.
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х+7=11-х
√82²-18²= √(82-18)(82+18) =√64·100 =8·10=80.
√65²-63² =√(65-63)(65+63) =√2·128 =√2·2·64 =2·8=16.
√113²-112² =√1·225 =15.
√√3^4·2²=√3²·2 =3√2.