(4c-1) вынесем за скобку:
(4c-1)(4c-12c+3)
0 и 1
0²=0×0=0
1²=1×1=1
0+1=1
Y₂-7y-8 =0 y2-12y+20=0 3x2-2x-5=0
d: 49+32=81 d= 144-80=64 d=4+60=64
y1= 7-9/2=-1 y1=12-8/2=2 x1=2-8/6=-1 y2=12+8/2=10 x2=2+8/6= 1 1
y2=7+9/2 =8 (y-2)(y-10) 3
(y+1)(y-8) 1
3y2-13y+12=0
d=169-144=25
y1=13-5/6=1.3.1
y2=18/6=3
3(y-1.3.1 )(y-3) (x+1)(x-1 .3 )