1
3a+3-na-n=3(a+1)-n(a+1)=(a+1)(3-n)
2
(x²-y²)/(3x-2x²+3y-2xy)=(x-y)(x+y)/[3(x+y)-2x(x+y)]=(x-y)(x+y)/[(x+y)(3-2x)]=
=(x-y)/(3-2x)
3
y=x² парабола
х -4 -3 -2 -1 0 1 2 3
у 16 9 4 1 0 1 4 9
у=-3х+4
х -4 1
у 16 1
Ответ х=-4,х=1
А-2
Б-4
В-3 по- моему точно правильно
(2x-y)/(x+y):(2x-y)/(x-y)*(x+y)/(x-y)=[(2x-y)(x-y)(x+y)]/[(x+y)(2x-y)(x+y)]=1
A³b³-8=
=(ab-2)*(a²b²+2ab+4)