Question

(x+y=П/2 (sin^2x-sin^2y=1

Answer 1

х=П/2-у

cos^2y-sin^2y=1

cos(2y)=1

2y=2П*k

y=П*k

x=П/2-П*k

k-любое целое число.

Answer 2

(x+y=П/2

(sin^2x-sin^2y=1

У=П/2 - х

Sin^2 x-sin^2 (П/2 -х)=1

Sin^2 x-cos^2 x=1

Sin^2 x- (1-sin^2 x)=1

Sin^2x -1 +sin^2x=1

2sin^2x=2

Sin^2x =1

Sinx=1

X=П/2+2Пn

Sin x= -1

X= -П/2 + 2Пn