- + - +
--------------------[-3]-----------(-2)-----------(2)-----------------
/////////////////////// //////////////
Ответ:
∞
∪
2a(c+d)-5b(c-d) = 2a(c+d)+5b(c+d)=(2a+5b)(c+d)
1 в корне из 6 = 1 , 1-100= -99
Х-√х-12=0
D=1-4×1×(-12)=1+48=49=7
x1=1+7/2=4 х2=1-7/2=-3
(х^2+3х)^2+2(х^2+3)-24=0
х^4+6х^3+11х-18=0
Замена: x^2=z
z^2+6z-7=0
D=36-4×1×(-7)=36+28=64=8
x1=-6+8/2=1 x2=-6-8/2=-7