Question

Log(5)7*Log(49)125=

Answer 1

Log₅5*log₄₉125=1,5

1.  log₄₉125=log_(₇²) 125=(1/2)*log₇125=(1/2)*log₇5³=(1/2)*3*log₇5=
=(3/2)*(log₅5/log₅7)=(3/2)*(1/log₅7)=1,5/log₅7

2.  log₅5*1,5/log₅7=1,5

Answer 2

=log(5)7 * log(7^2)5^3 = log(5)7 * 1/(log(5^3)7^2) = log(5)7 * 1/(2/3*log(5)7) = 1 * 3/2 = 1,5