-4х квадрат + 3х<span>=0
Д</span>= 3 квадрат -4 умнож на -4= 9+16 <span>=25
Х1</span>= -3-5 ; 2= -4
Х2=-3+5;2 <span>=1</span>
<span>ОТВЕТ: x = (arctg(1/3) +,-pi*n)/2, </span>
<span>где n - период, n =0, 1, 2, 3, ..</span>
<span>V3 sin 2 x - cos2x = 0, </span>
<span>(здесь V - квадратный корень), </span>
<span>3 sin 2 x = cos2x, </span>
<span>3*sin2x/cos2x = 1, </span>
<span>3tg2x = 1, </span>
<span>tg2x = 1/3, </span>
<span>2x = аrctg(1/3) +,-pi*n, </span>
<span>n - период, n =0, 1, 2, 3, ..</span>
<span>x = (arctg(1/3) +,-pi*n)/2</span>
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1 не знаю
2)sin²α=1-cos²α
sin²α=1-0.36
sinα=0.6
tgα=sinα/cosα=0.6/0.8=0.75
3)sin²α=1-cos²α
sin²α=1-(√3/2)²
sin²α=1/4
sinα=-0.5(т.к на окружности <span>3π/2 меньше α меньше 2π знак минус)</span>