<span>ОТВЕТ: x = (arctg(1/3) +,-pi*n)/2, </span>
<span>где n - период, n =0, 1, 2, 3, ..</span>
<span>V3 sin 2 x - cos2x = 0, </span>
<span>(здесь V - квадратный корень), </span>
<span>3 sin 2 x = cos2x, </span>
<span>3*sin2x/cos2x = 1, </span>
<span>3tg2x = 1, </span>
<span>tg2x = 1/3, </span>
<span>2x = аrctg(1/3) +,-pi*n, </span>
<span>n - период, n =0, 1, 2, 3, ..</span>
<span>x = (arctg(1/3) +,-pi*n)/2</span>