Как то так)))
<span>sin3x+sin5x+2sin²(x/2)=1</span><span>2sin4x•cosx=1-2sin²(x/2)</span><span>2sin4x•cosx=cosx</span><span>cosx•(2sin4x-1)=0</span><span>1) cosx=0 => x=π/2+πn</span><span>2) sin4x=½ => 4x=(-1)^n•π/6+πn => x=(-1)^n•π/24+(π/4)•n</span>