<span>y=x^3 + 2x^5
y`=3x^2+10x^4</span>
Log2(x+4)/(3x-2)=2. (x+4)/(3x-2)=4. (x+4)=(3x-2)•
Пусть x - 3 = t
t^2 + 9t + 20 = 0
D= 81 - 80 = 1
t1 = ( - 9 + 1)/2 = - 8/2 = - 4;
t2 = ( - 9 - 1)/2 = - 10/2 = - 5;
x - 3 = - 4
x = - 1
x - 3 = - 5
x = - 2
5x+(11-7x)=5x+11-7x=-2x+11
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