Task/27151545
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<span>(cos5a+5cos3a+10cosa)/(cosa)^5=
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</span>решение :<span>
* * * cos</span>²φ =(1+cos2φ)/2 ; cosα*cosβ =( cos(α+β)+ cos(α-β) )/2 * * *
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cos⁵α =(cosα)*(cos²α)² =(cosα)* ( (1+cos2α) /2 )² =(cosα)* (1+2cos2α+cos²2α)/4 = (cosα)*(1+2cos2α+(1+cos4α)/2 )/4 =
(cosα)*(3 +4cos2α +cos4α*cosα)/8=(3cosα+4cos2α*cosα +cos4α*cosα) /8=(3cosα+2cosα+2cos3α +(cos5α+cos3α)/2)/8 =(cos5α+5cos3α+10cosα)/16 .
Следовательно :
(cos5α+5cos3α+10cosα) / (cos⁵α ) =
(cos5α+5cos3α+10cosα) / ( (cos5α+5cos3α+10cosα)/16 ) = 16.
ответ: 16
F'(x) = 4x^3-12x^2=4x^2(x-3) = 0
x=0 x=3
- 0 - 0 +
___,____,____
x=0 x=3
y=0 y=-27
АС = 1/3 м
ВС = 1/3-1/12 = 1/4 м
АВ= 1/4 - 1/8 = 1/8 м
P= 1/3+1/4+1/8 = 17/24 м
1) 1 1\6 + 2 2\5 = 1 5\30 + 2 12\30 = 3 17\10 Часа - на готовку и стирку
2) 3 17\10 + 3\4 = 3 34\20 + 15\20 = 3 49\20 = 3 + 2.45 = 5.45 часа (ОТВЕТ)