ОДЗ: (2x-6)(5-x)>0
2x-6>0 x>3 2x-6<0 x<3 5-x>0 x<5 <em> x∈(3;5) </em> 5-x<0 x>5 x∉.
А) (х+у)^2
б)х^2+y^2
)a^3+b^3
)(a-b)^3
)a^3-b^3
)(a+b)^3
Task/26092386
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см приложение
A/(a-1)(a+1)+(a²+a-1)/[a²(a-1)+(a-1)]+(a²-a-1)/[a²(a+1)+(a+1)]-2a³/(a²-1)(a²+1)=
=a/(a-1)(a+1)+(a²+a-1)/(a-1)(a²+1)+(a²-a-1)/(a+1)(a²+1)-2a³/(a-1)9a+1)(a²+1)=
=(a³+a+a³+a²+a²+a-a-1+a³-a²-a²+a-a+1-2a³)/(a-1)(a+1)(a²+1)=
=(a³+a)/(a²-1)9a²+1)=a(a²+1)/(a²-1)9a²+1)=a/(a²-1)
Решение во вложения……………..