Question

Найдите корень уравнения

Answer 1

$\frac{x-7}{x+3}=\frac{x-3}{x+9};\\\\x+3 \neq 0; x+9 \neq 0;\\\\x \neq -3;x \neq -9;\\\\(x-7)(x+9)=(x+3)(x-3);\\\\x^2-7x+9x-63=x^2-9;\\\\2x-63=-9;\\\\2x=-9+63;\\\\2x=54;\\\\x=54:2;\\\\x=27$