Забыла как решать.Помогите.
Найдите значение дроби:
8<span>{16}</span>
------ =
16<span>^{12}</span>
<span>2)15<span>а^{2</span><span>}-10ab</span></span>
<span><span>---------------------</span></span>
<span><span> 3ab-2b<span>^{2}</span></span></span>
При а= -2,b= -0,1
Заранее огромное спасибо:)
1) 8<span>¹⁶ / 16¹² = 2⁴⁸ / 2⁴⁸ = 1 </span>
<span></span>
<span>2) (15<span>а²</span><span>- 10ab)/(<span><span>3ab-2b²) = 5а(3а - 2<span><span>b</span></span>)/(<span><span>b</span></span>·<span><span><span><span>(3а - 2<span><span>b</span></span>)</span></span></span></span>) = 5а/<span><span><span><span><span><span>b</span></span></span></span></span></span></span></span></span></span>
<span><span><span><span>5а/<span><span><span><span><span><span>b</span></span></span></span></span></span></span></span></span></span> = 5·(-2)/(-0,1) = -10/(-0,1) = 100
x² - 12x +32 = (x-8)(x-4)