![4 x^{2} -12x+9 \leq 0 \\ 4 x^{2} -12x+9=0 \\ D=144-144=0 \\ x_{0} = \frac{12}{8} =1.5 \\ x-1.5 \leq 0 \\ \\ \\](https://tex.z-dn.net/?f=4+x%5E%7B2%7D+-12x%2B9+%5Cleq+0+%5C%5C+4+x%5E%7B2%7D+-12x%2B9%3D0+%5C%5C+D%3D144-144%3D0+%5C%5C++x_%7B0%7D+%3D+%5Cfrac%7B12%7D%7B8%7D+%3D1.5+%5C%5C+x-1.5+%5Cleq+0+%5C%5C++%5C%5C++%5C%5C+)
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1.5
![x\in (- \infty ;1.5]](https://tex.z-dn.net/?f=+x%5Cin+%28-+%5Cinfty+%3B1.5%5D+)
2x^2-2y^2+2x=0
перенесем центр в точку (-0,5;0)
x=x'-0,5
x=y'
2(x-0,5)^2-2y'+2(x-0,5)=2*(x'-0,5)(x'-0,5+1)-2y'=2(x'-0,5)(x'+0,5)-2y'=
=2x'^2-1/2-2y'^2=0
4x^2-4y^2=1
x^2/(1/2)^2-y^2/(1/2)^2=1
гипербола
![-3,25\leq\frac{1-4x}{3}<1,25\\\\-3,25*3\leq\frac{1-4x}{3}*3<1,25*3\\\\-9,75\leq1-4x<3,75\\\\-9,75-1\leq1-4x-1<3,75-1\\\\-10,75\leq -4x<2,75|:-4\\\\-0,6875<x\leq2,6875\\\\x\in(-0,6875;2,6875]](https://tex.z-dn.net/?f=-3%2C25%5Cleq%5Cfrac%7B1-4x%7D%7B3%7D%3C1%2C25%5C%5C%5C%5C-3%2C25%2A3%5Cleq%5Cfrac%7B1-4x%7D%7B3%7D%2A3%3C1%2C25%2A3%5C%5C%5C%5C-9%2C75%5Cleq1-4x%3C3%2C75%5C%5C%5C%5C-9%2C75-1%5Cleq1-4x-1%3C3%2C75-1%5C%5C%5C%5C-10%2C75%5Cleq+-4x%3C2%2C75%7C%3A-4%5C%5C%5C%5C-0%2C6875%3Cx%5Cleq2%2C6875%5C%5C%5C%5Cx%5Cin%28-0%2C6875%3B2%2C6875%5D)
Ответ : 3 целых числа : 0 ; 1 ; 2