Y(x)=3x²-2x+1
y(2x-1)=3(2x-1)²-2(2x-1)+1=12x²-12x+3-4x+2+1=12x²-16x+6
Ответ:
x^2-xy-4x+4y=x(x-y)-4(x+y)
(5-t)(-t-5)-(4+t)² = (-t)²-25-(16+8t+t²) = (-t)²-25-16-8t-t² = - 41 - 8t
Д и е не знаю. А так эти легко решаются)))))
Log₀ ₅ 0.5 log₉ 1/81 - 7^(log₇ 2)= 1 * log₉ 9⁻² - 2 = -2 - 2 = -4
(loga a = 1 a>0 a<>1)
log₃ 6 + log₃ 18 - log₃ 4 = log₃ (6*18 / 4) = log₃ 3³ = 3
9^(0.5 - log₃ 2) - log₃ (log₂ 8)) = (3^2)^0.5 / (3^2)^log₃ 2 - log₃(log₂ 2³)= 3 / 3^log₃ 4 - log₃ 3 = 3/4 -1 = -1/4 =-0.25