![\displaystyle\bigg(\frac{\sqrt{q}}{p-\sqrt{pq}}+\frac{\sqrt{p}}{q-\sqrt{pq}}\bigg)\cdot\frac{p\sqrt{q}+q\sqrt{p}}{p-q}=\\\\\\=\bigg(\frac{\sqrt{q}}{\sqrt{p}(\sqrt{p}-\sqrt{q})}-\frac{\sqrt{p}}{\sqrt{q}(\sqrt{p}-\sqrt{q})}\bigg)\cdot\frac{\sqrt{pq}(\sqrt{p}+\sqrt{q})}{(\sqrt{p}-\sqrt{q})(\sqrt{p}+\sqrt{q})}=\\\\\\=\frac{q-p}{\sqrt{pq}(\sqrt{p}-\sqrt{q})} \cdot\frac{\sqrt{pq}}{\sqrt{p}-\sqrt{q}}=\frac{(\sqrt{q}-\sqrt{p})(\sqrt{q}+\sqrt{p})}{(\sqrt{q}-\sqrt{p})^2}=\frac{\sqrt{q}+\sqrt{p}}{\sqrt{q}-\sqrt{p}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cbigg%28%5Cfrac%7B%5Csqrt%7Bq%7D%7D%7Bp-%5Csqrt%7Bpq%7D%7D%2B%5Cfrac%7B%5Csqrt%7Bp%7D%7D%7Bq-%5Csqrt%7Bpq%7D%7D%5Cbigg%29%5Ccdot%5Cfrac%7Bp%5Csqrt%7Bq%7D%2Bq%5Csqrt%7Bp%7D%7D%7Bp-q%7D%3D%5C%5C%5C%5C%5C%5C%3D%5Cbigg%28%5Cfrac%7B%5Csqrt%7Bq%7D%7D%7B%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D-%5Cfrac%7B%5Csqrt%7Bp%7D%7D%7B%5Csqrt%7Bq%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%5Cbigg%29%5Ccdot%5Cfrac%7B%5Csqrt%7Bpq%7D%28%5Csqrt%7Bp%7D%2B%5Csqrt%7Bq%7D%29%7D%7B%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%28%5Csqrt%7Bp%7D%2B%5Csqrt%7Bq%7D%29%7D%3D%5C%5C%5C%5C%5C%5C%3D%5Cfrac%7Bq-p%7D%7B%5Csqrt%7Bpq%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%20%5Ccdot%5Cfrac%7B%5Csqrt%7Bpq%7D%7D%7B%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%7D%3D%5Cfrac%7B%28%5Csqrt%7Bq%7D-%5Csqrt%7Bp%7D%29%28%5Csqrt%7Bq%7D%2B%5Csqrt%7Bp%7D%29%7D%7B%28%5Csqrt%7Bq%7D-%5Csqrt%7Bp%7D%29%5E2%7D%3D%5Cfrac%7B%5Csqrt%7Bq%7D%2B%5Csqrt%7Bp%7D%7D%7B%5Csqrt%7Bq%7D-%5Csqrt%7Bp%7D%7D)
если <em>р = 81; q = 100:</em>
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<span>1)log 0.36 по основанию 0,6- log 0.027 по основанию 0,3
2)8^(log132 по основанию 8</span>
1)2-3=-1
2)тут 8 и лог8ми сокращаются остаётся 132
sinα+sin3α=2sin(α+3α)/2*cos(α-3α)/2=2sin2αcosα
Почему задание не написал(а)?!
1)...=z^2+4z-z-4=z^2+3z-4
(ЕСЛИ ДИСКРИМИНАНТ НАДО НАЙТИ, то
пиши следующее...
D=25
z(1)=(-3-5)/2=-4
z(2)=(-3+5)/2=1
Ответ: -4; 1.)
2)...=mn-m+6n-6
3)...=bc+5b+4c+20