2 Mg + O2 = 2 MgO
MgO + 2 HCl = H2O + MgCl2
Na2O + H2O = 2 NaOH
6 NaOH + P2O5 = 3 H2O + 2 Na3PO4
AgNO3 + HCl = AgCl(белый осадок хлорида серебра) + HNO3
AgNO3 + NaCl = AgCl + NaNO3
Ag+ + NO3- + Na+ + Cl- = AgCl↓ + Na+ + NO3-
Ag+ + Cl- = AgCl↓
HCl + AgNO3 = AgCl↓ + HNO3
H+ + Cl- + Ag+ + NO3- = AgCl↓ + H+ + NO3-
Ag+ + Cl- = AgCl↓
Вот, по 10 на каждый
2K+2HI=2KI+H2
2K+2HBr=2KBr+H2
2K+2HCl=2KCl+H2
2K+2HF=2KF+H2
2K+H2SO4=K2SO4+H2
2K+H2SO3=K2SO3+H2
2K+H2CO3=K2CO3+H2
2K+H2S=K2S+H2
2K+H2SiO3=K2SiO3+H2
6K+2H3PO4=2K3PO4+3H2
Mn+2HI=MnI2+H2
Mn+2HBr=MnBr2+H2
Mn+2HCl=MnCl2+H2
Mn+2HF=MnF2+H2
Mn+H2SO4=MnSO4+H2
Mn+H2SO3=MnSO3+H2
Mn+H2CO3=MnCO3+H2
Mn+H2S=MnS+H2
Mn+H2SiO3=MnSiO3+H2
3Mn+2H3PO4=Mn3(PO4)2+3H2
2Al+6HI=2AlI3+3H2
2Al+6HBr=2AlBr3+3H2
2Al+6HCl=2AlCl3+3H2
2Al+6HF=2AlF3+3H2
2Al+3H2SO4=Al2(SO4)3+3H2
2Al+2H3PO4=2AlPO4+3H2
2Al+6HClO4=2Al(ClO4)3+3H2
2Al+6HClO3=2Al(ClO3)3+3H2
2Al+6HClO2=2Al(ClO2)3+3H2
2Al+6HClO=2Al(ClO)3+3H2
Насчет последних двух я не совсем уверена.
<span>MgCl</span>₂ <span>+ 2NaOH = Mg(OH)</span>₂ <span>+ 2NaCl
Mg</span>⁺² <span>+ 2Cl</span>⁻ <span>+ 2Na</span>⁺ <span>+ 2OH</span>⁻ <span>= Mg(OH)</span>₂<span>+ 2Na</span>⁺ <span>+ 2Cl</span>⁻
<span>Mg</span>⁺² <span>+ 2OH</span>⁻ <span>= Mg(OH)</span>₂
<span>
MgCl</span>₂ <span>+ 2AgNO</span>₃ <span>= 2AgCl + Mg(NO</span>₃<span>)</span>₂<span>
Mg</span>⁺²<span> + 2Cl</span>⁻ <span>+ 2Ag</span>⁺ <span>+ 2NO</span>₃⁻ <span>= 2AgCl + Mg</span>⁺² <span>+ 2NO</span>⁻
<span>2Ag</span>⁺ <span>+ 2Cl</span>⁻ <span>= 2AgCl
MgCl</span>₂ <span>+ Na</span>₂<span>CO</span>₃ <span>= MgCO</span>₃ <span>+ 2NaCl
Mg</span>⁺² <span>+ 2Cl</span>⁻ <span>+ 2Na</span>⁺ <span>+ CO</span>₃²⁻ <span>= MgCO</span>₃ <span>+ 2Na</span>⁺ <span>+ 2Cl</span>⁻
<span>Mg</span>⁺² <span>+ CO</span>₃²⁻ <span>= MgCO</span>₃
<span>
MgCl</span>₂ <span>+ H</span>₂<span>SO</span>₄ <span>= MgSO</span>₄ <span>+ 2HCl
Реагирует при условии, что конц серная кислота прикапывается к соли, хлороводород улетает. В водном растворе не реагирует</span>
