A(t)=cos(t/2)
v(t)=∫cos(t/2)dt+C=2sin(t/2)+C
v(<span>2π/3)=2sin(</span><span>2π/6)+C</span>=√3
2sin(π/3)+C=√3
2*√3/2+C=√3
C=0
v(t)=2sin(t/2)
x(t)=∫2sin(t/2)dt+C=-4cos(t/2)+C
x(2π/3)=-4cos(2π/6)+C=2
-4cos(π/3)+C=2
-4/2+C=2
-2+C=2
C=4
x(t)=-4cos(t/2)+4
2x - ay + bz
a = 3c
b = 14c^3
x = 5c^3 + 2
y = 6c^2 - c + 13
z = 5c - 1
2(5c^3 + 2) - 3c*(6c^2 - c + 13) + 14c^3*(5c - 1) =
= 10c^3 + 4 - 3c*6c^2 + 3c*c - 39c + 70c^4 - 14c^3 =
= 10c^3 + 4 - 18c^3 + 3c^2 - 39c + 70c^4 - 14c^3 =
= 70c^4 - 22c^3 + 3c^2 - 39c + 4
<span>(3x + 1 ) - 5 × (2x+2)=
=</span><span>3x + 1 - 10x-10 =
</span>=-7<span>x -9</span>