Question

2помогите плизззззззз

Answer 1

$2\cdot(6\frac{3}{8}-2\frac{3}{4})\cdot(-4)+\frac{7}{18}\cdot9=-25\frac{1}{2}$

 

1) $6\frac{3}{8}-2\frac{3}{4}=4\frac{3}{8}-\frac{3}{4}=3\frac{11}{8}-\frac{6}{8}=3\frac{5}{8}$

 

2) $2*3\frac{5}{8}=2*\frac{29}{8}=\frac{29}{4}=7\frac{1}{4}$

 

3) $7\frac{1}{4}\cdot(-4)=\frac{29}{4}\cdot(-4)=-29$

 

4) $\frac{7}{18}*9=\frac{7}{2}=3\frac{1}{2}$

 

5) $-29+3\frac{1}{2}=-26+\frac{1}{2}=-25\frac{1}{2}$

Answer 2

6-2=4

3/8-3/4=3/8-6/8=-3/8

2*4-2*3/8=8-3/4=7,25

7,25*(-4)=-29

7/18*9=7/2=3,5

-29+3,5=-25,5