![\frac{x-1+\frac{1}{x}}{1-\frac{1}{x}}\; ,\; \; \; \; ODZ:\; \; x\ne 0\; \; i\; \; 1-\frac{1}{x}\ne 0\; \; \to \; \; x\ne 0\; i\; \; \; \frac{x-1}{x}\ne 0\; ,\\\\x\ne 0\; \; i\; \; x\ne 1\; \; \Rightarrow \; \; x\in (-\infty ,0)\cup (0,1)\cup (1,+\infty )\\\\x=-1:\; \; \frac{x-1+\frac{1}{x}}{1-\frac{1}{x}}=\frac{x^2-x+1}{x-1}=\frac{-1-1-1}{1+1}=-\frac{3}{2}=-1,5\\\\x=\frac{1}{2}:\; \; \frac{x^2-x+1}{x-1}=\frac{\frac{1}{4}-\frac{1}{2}+1}{\frac{1}{2}-1}=\frac{\frac{3}{4}}{-\frac{1}{2}}=-\frac{3\cdot 2}{4\cdot 1}=-\frac{3}{2}=-1,5](https://tex.z-dn.net/?f=%5Cfrac%7Bx-1%2B%5Cfrac%7B1%7D%7Bx%7D%7D%7B1-%5Cfrac%7B1%7D%7Bx%7D%7D%5C%3B+%2C%5C%3B+%5C%3B+%5C%3B+%5C%3B+ODZ%3A%5C%3B+%5C%3B+x%5Cne+0%5C%3B+%5C%3B+i%5C%3B+%5C%3B+1-%5Cfrac%7B1%7D%7Bx%7D%5Cne+0%5C%3B+%5C%3B+%5Cto+%5C%3B+%5C%3B+x%5Cne+0%5C%3B+i%5C%3B+%5C%3B+%5C%3B+%5Cfrac%7Bx-1%7D%7Bx%7D%5Cne+0%5C%3B+%2C%5C%5C%5C%5Cx%5Cne+0%5C%3B+%5C%3B+i%5C%3B+%5C%3B+x%5Cne+1%5C%3B+%5C%3B+%5CRightarrow+%5C%3B+%5C%3B+x%5Cin+%28-%5Cinfty+%2C0%29%5Ccup+%280%2C1%29%5Ccup+%281%2C%2B%5Cinfty+%29%5C%5C%5C%5Cx%3D-1%3A%5C%3B+%5C%3B+%5Cfrac%7Bx-1%2B%5Cfrac%7B1%7D%7Bx%7D%7D%7B1-%5Cfrac%7B1%7D%7Bx%7D%7D%3D%5Cfrac%7Bx%5E2-x%2B1%7D%7Bx-1%7D%3D%5Cfrac%7B-1-1-1%7D%7B1%2B1%7D%3D-%5Cfrac%7B3%7D%7B2%7D%3D-1%2C5%5C%5C%5C%5Cx%3D%5Cfrac%7B1%7D%7B2%7D%3A%5C%3B+%5C%3B+%5Cfrac%7Bx%5E2-x%2B1%7D%7Bx-1%7D%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B4%7D-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7B%5Cfrac%7B1%7D%7B2%7D-1%7D%3D%5Cfrac%7B%5Cfrac%7B3%7D%7B4%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%7D%3D-%5Cfrac%7B3%5Ccdot+2%7D%7B4%5Ccdot+1%7D%3D-%5Cfrac%7B3%7D%7B2%7D%3D-1%2C5)
При х=0 и х=1 выражение не имеет смысл, при х=-1 и х=1/2 выражение принимает значение (-1,5) .
1) log2(x^2+4x+1)+log2(2)=log2(6x*2)
log2((x^2+4x+1)*2)=log2(6x+2)
log2(2x^2+8x+2)=log2(6x+2)
2x^2+8x+2=6x+2
2x^2+8x=6x
x^2+4x=3x
x^2+4x-3x=0
x^2+x=0
x(x+1)=0
x=0
x+1=0
x=0
x=-1
Ответ: 0
F(x)=4cosx-3sinx-5
4cosx-3sinx-5=0,подношу к квадрату
16cos^2x-24cosxsinx+9sin^2x=25
8(1-cos2x)-0+4.5(1-cos2x)=25
3.5cos2x=12.5
cos2x=3.6
x=(arccos3.6)/2+пn,где п это число (пи),n принадлежит Z
Ответ:
в ответ: x1=-0,30; x2=0,54; x3=0,29