10y/(3y-2)(3y+2) +(y-5)/(3y+2) +(y-3)/(3y-2)=0
10y+(3y-2)(y-5)+(y-3)(3y+2)=0
10y+3y²-15y-2y+10+3y²+2y-9y-6=0
6y²-14y+4=0
D=196-96=100
y1=(14-10)/12=1/3
y2=(14+10)/12=2
X^2+7x-8=0
D=7^2-4*1*(-8)=81
x1=(-7-9)/2=-8
x2=(-7+9)/2=1
Итак, x^2+7x-8= (x+8)(x-1)
2*x+3/4+x/3=x+1/2
x*(2+1/3-1)=1/2-3/4
x*4/3= - 1/4
x= - 3/16
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х^3/x^2+4
(область определения)
ОДЗ: x^2≠0 (-∞;0) u (0;+∞)