![\frac{2x+1}{x+9} \leq 1\\\\ \frac{2x+1}{x+9}-1 \leq 0\\\\ \frac{2x+1-(x+9)}{x+9} \leq 0\\\\ \frac{2x+1-x-9}{x+9} \leq 0\\\\ \frac{x-8}{x+9} \leq 0](https://tex.z-dn.net/?f=+%5Cfrac%7B2x%2B1%7D%7Bx%2B9%7D+%5Cleq+1%5C%5C%5C%5C+%5Cfrac%7B2x%2B1%7D%7Bx%2B9%7D-1+%5Cleq+0%5C%5C%5C%5C+%5Cfrac%7B2x%2B1-%28x%2B9%29%7D%7Bx%2B9%7D+%5Cleq+0%5C%5C%5C%5C+%5Cfrac%7B2x%2B1-x-9%7D%7Bx%2B9%7D+%5Cleq+0%5C%5C%5C%5C+%5Cfrac%7Bx-8%7D%7Bx%2B9%7D+%5Cleq+0+++++)
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________________[-9]______________[8]_______________
![x\in [-9;8]](https://tex.z-dn.net/?f=x%5Cin+%5B-9%3B8%5D)
Ответ:
Объяснение:
Пусть lgx=t, Тогда t^2-4t-5=0
t1=1 = > lgx=1; x=10
t2 = - 5=> lgx = - 5; lgx=-5lg10; lgx=lg (10) ^ (-5); x=0,00001
Ответ: 0,00001; 10
1) 4(2a-3b)
2) a(3-b)
3) a(6x-y)
1)-3х-6=5-2х;
-3х+2х=5+6;
-х=11;
х=-11;
2)3-5х-5=6-4х;
-5х+4х=5-3;
-х=2;
х=-2;
Ответ:1)-11; 2)-2.