Question

разлжите на множетели трёхчлен-21х2+х+2

Answer 1

$-21x^2+x+2=-21(x-\frac{1}{3})(x+\frac{2}{7})=(1-3x)(7x+2)\\ D=1-4*(-21)*2=169\\x_1=\frac{12}{-42}=\frac{-2}{7}\\ x_1=\frac{-14}{-42}=\frac{1}{3}$

Answer 2

-21х2+х+2=0

D=1+168=169

x1=(1-13) \ (-42)

x2=(1+13) \ (-42)

-21(x-(2/7))(x+(1/3))