Question

3.5^(3/5)*0.25^(-9/5)*7^(2/5) решите плз

Answer 1

$3.5^{ \frac{3}{5} }*0.25^{ -\frac{9}{5} }*7^{ \frac{2}{5} }=7^{ \frac{3}{5} }*2^{ -\frac{3}{5} }*(2^{-2})^{ -\frac{9}{5} }*7^{ \frac{2}{5} }= \\ =7^{ \frac{3}{5} }*2^{ -\frac{3}{5} }*2^ \frac{18}{5} *7^{ \frac{2}{5} }=7*2^3=7*8=56$