1) f(x)=√(4-8x)
ООФ: 4-8x≥0, 8x≤4, x≤1/2, x∈(-∞,1/2]
2)f(x)=6/(12x-3)
ООФ: 12x-3≠0, 12x≠3, x≠1/4, x∈(-∞,1/4)∨(1/4,∞)
Y = <span>1+12х-9х²;
y '(x) = 12 - 18 x;
y'= 0;
12 - 18 x = 0;
- 18x = -12;
x = 12/18 = 2/3;
y(2/3) = 1 + 12/1 * 2/3 - 9/1 * (4/9) = 1 + 8 - 4 = 5</span>
Смотри рисунок ниже.................
{3x<22, 2x>4
{x<22/3, x>2
{x<7 1/3 , x>2
(2; 7 1/3)
ответ: 5, 6