Question

Сократить дробь, 9 класс

Answer 1

Решение во вложении
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Answer 2

$\displaystyle \frac{a^{2}-13a+30}{-2a^{2}+5a+3}= \frac{(x-10)(x-3)}{-2(x+0,5)(x-3)}= \frac{x-10}{-2x-1}=-\frac{x-10}{2x+1}; \\ \\ D_{1}=b^{2}-4ac=169-120=49 \\ D_{2}=25+24=49 \\ \\ a_{1,2,3,4}= \frac{-bб \sqrt{D}}{2a} \\ \\ a_{1}=10 \\ a_{2}=3 \\ a_{3}=-0,5 \\ a_{4}=3$