<span>(х+1)^3(х-1)>0</span>
++++++++-1------------1+++++++++++
x= (- бесконечность, -1)U(1, + бесконечность)
Числитель = 15·13^(2n+2) = 15·13^2n·13^2=15·169^n·13^2
знаменатель = 169^(n -1) = 169^n·169^-1= 169^n·13^-2
дробь сократим на 169^n
Ответ: 15·13^4
1) упростим выражение:
![{x}^{2} ( {x}^{2} - 3x + 1) - 2x( {x}^{3} - 3 {x}^{2} + x) = {x}^{4} - 3 {x}^{3} + {x}^{2} - 2 {x}^{4} + 6 {x}^{3} - 2 {x}^{2} = - {x}^{4} + 3 {x}^{3} - {x}^{2} = - {x}^{2} ( {x}^{2} - 3x + 1)](https://tex.z-dn.net/?f=++%7Bx%7D%5E%7B2%7D+%28+%7Bx%7D%5E%7B2%7D++-+3x+%2B+1%29+-+2x%28+%7Bx%7D%5E%7B3%7D++-+3+%7Bx%7D%5E%7B2%7D++%2B+x%29+%3D++%7Bx%7D%5E%7B4%7D++-+3+%7Bx%7D%5E%7B3%7D++%2B++%7Bx%7D%5E%7B2%7D++-+2+%7Bx%7D%5E%7B4%7D++%2B+6+%7Bx%7D%5E%7B3%7D++-+2+%7Bx%7D%5E%7B2%7D++%3D++-++%7Bx%7D%5E%7B4%7D++%2B+3+%7Bx%7D%5E%7B3%7D++-++%7Bx%7D%5E%7B2%7D++%3D+++-+%7Bx%7D%5E%7B2%7D+%28+%7Bx%7D%5E%7B2%7D++-+3x+%2B+1%29)
2) подставим наше значение х:
![- ({1 \frac{1}{3} )}^{2} \times ( {(1 \frac{1}{3} )}^{2} - 3 \times 1 \frac{1}{3} + 1) = - {( \frac{4}{3} )}^{2} \times ( {( \frac{4}{3} )}^{2} - 3 \times \frac{4}{3} + 1) = - \frac{16}{9} \times ( \frac{16}{9} - 4 + 1) = - \frac{16}{9} \times (1 \frac{7}{9} - 3) = \frac{16}{9} \times ( - 1 \frac{2}{9} ) = - \frac{16 \times 11}{9 \times 9} = - \frac{176}{81} = - 2 \frac{14}{81}](https://tex.z-dn.net/?f=+-+%28%7B1+%5Cfrac%7B1%7D%7B3%7D+%29%7D%5E%7B2%7D++%5Ctimes+%28+%7B%281+%5Cfrac%7B1%7D%7B3%7D+%29%7D%5E%7B2%7D++-+3+%5Ctimes+1+%5Cfrac%7B1%7D%7B3%7D++%2B+1%29+%3D++-++%7B%28+%5Cfrac%7B4%7D%7B3%7D+%29%7D%5E%7B2%7D++%5Ctimes+%28+%7B%28+%5Cfrac%7B4%7D%7B3%7D+%29%7D%5E%7B2%7D++-+3+%5Ctimes++%5Cfrac%7B4%7D%7B3%7D++%2B+1%29+%3D++-++%5Cfrac%7B16%7D%7B9%7D++%5Ctimes+%28+%5Cfrac%7B16%7D%7B9%7D++-+4+%2B+1%29+%3D++-++%5Cfrac%7B16%7D%7B9%7D++%5Ctimes+%281+%5Cfrac%7B7%7D%7B9%7D++-+3%29+%3D++%5Cfrac%7B16%7D%7B9%7D++%5Ctimes+%28+-+1+%5Cfrac%7B2%7D%7B9%7D+%29+%3D++-++%5Cfrac%7B16+%5Ctimes+11%7D%7B9+%5Ctimes+9%7D++%3D++-++%5Cfrac%7B176%7D%7B81%7D++%3D++-+2+%5Cfrac%7B14%7D%7B81%7D+)
Это алгебра восьмого класса?