1 ответ:
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64x²+16x+1=0,x≠0
(8x+1)²=0
x=-1/8
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1)(c-2)/(c+2) -2/(c-2)=(c²-4c+4-c²-2c)/(c-2)(c+2)=(4-6c)/(c-2)(c+2)=2(2-3c)/(c-2)(c+2)
2)2(2-3c)/(c-2)(c+2)*(c+2)/(2-3c)=2/(c-2)
2
3
64x²+16x+1=0,x≠0
(8x+1)²=0
x=-1/8
4
1)(c-2)/(c+2) -2/(c-2)=(c²-4c+4-c²-2c)/(c-2)(c+2)=(4-6c)/(c-2)(c+2)=2(2-3c)/(c-2)(c+2)
2)2(2-3c)/(c-2)(c+2)*(c+2)/(2-3c)=2/(c-2)