1.1.1
2-5х=11 -2х
-5х+2х=11-2
-3х=9
х=-3
1.1.2
-4 (3-х)=2х+7
4х-2х=7+12
2х=19
х=19/2=9.5
1.1.3
7/8х=19 1/4
х=2*11
х=22
1)ОДЗ: х-5 не равен 0
х не равен 5
Метод Лягерра, точность <span> 1e-3</span>
<span>x1 ≈ 0.666666552553487
<span>P(x1) ≈ 0 <span>iter = </span>4
</span><span>x2<span> ≈ 0.749999727053003 − i ∙ 0.66143770861557
</span>P(x2) ≈ 0 <span>iter = </span>3
</span><span>x3<span> ≈ 0.750000123124048 + i ∙ 0.661438012106969
</span>P(x3) ≈ 0 <span>iter = </span>3
</span><span>x4<span> ≈ 1.0000003286761
</span>P(x4) ≈ 0 <span>iter = </span>1
</span><span>x5<span> ≈ 1.49999993526003
</span>P(x5) ≈ 0 <span>iter = </span>1</span></span>