Question

Людии!!!Хелпппп! 5.77,5.78 задания!!!!!!

Answer 1

$1)\; \; \left \{ {{3^{x}\cdot 2^{y}=\frac{1}{9}} \atop {y-x=2}} \right. \; \left \{ {{3^{x}\cdot 2^{x+2}=\frac{1}{9}} \atop {y=x+2}} \right. \\\\2^{x}\cdot 2^2=\frac{1}{3^2\cdot 3^{x}}\; ;\quad 2^{x}\cdot 3^{x}=\frac{1}{2^2\cdot 3^2}\; ;\quad 6^{x}=6^{-2}\; ;\; \; x=-2\\\\y=-2+2=0\\\\Otvet:\; \; (-2,0)\\\\2)\quad \left \{ {{2^{y}=200\cdot 5^{x}} \atop {x+y=1}} \right. \; \left \{ {{2^{y}=2\cdot (2\cdot 5)^2\cdot 5^{1-y}} \atop {x=1-y}} \right.$

  $\left \{ {{2^{y}\cdot 5^{y}=10^3} \atop {x=1-y}} \right.$ 

 $\left \{ {{y=3} \atop {x=1-y}} \right. \; \left \{ {{y=3} \atop {x=-2}} \right. \\\\Otvet:\; \; (-2,3).$