A) M(2;20) 20=k×2² k=5
б)N(-3;27) 27=k×(-3)² k=3
в)K(-1;10) 10=k×(-1)² k=10
г)L(4;-96) -96=k×4² k=-6
<span> (2х+1)*(х-4)
2х*х+2х*(-4)+1*х+1*(-4)
2х</span>²-8х+х-4
2х²-7х-4=0
д=(-7)²-4*2*(-4)=49+32=81
х1=(7+√81)/2*2=16/4=4
х2=(7-√81)/2*2=-2/4=-0,5
Ответ: х1=4,х2=-0,5
1
2sin(5x/2)cos(3x/2)+2sin(5x/2)cos(x/2)=2sin(5x)/2*(cos(3x/2)+cos(x/2))=
=2sin(5x/2)*2cos(x)8cos(x/2)=4sin(5x/2)*cos(x)*cos(x/2)
2
-2sin(-3y)*sin5y-2cos(y/2)*cos5y=2(sin5y*sin3y+cos(y/2)*cos5y)
3
1-cos2a/(-sin2a)*(-ctga)=1-ctg2a*tga=1-tga/tg2a=1-tga*(1-tg²a)/(2tga)=
=1-(1-tg²a)/2=(2-1+tg²a)/2=(1+tg²a)/2=1/2cos²a
3
-sin2a/(1+cos2a) *ctga=[-2sina*cosa/(2cos²a)]*cosa/sina=-2
P=(1-0,02)*(1-0,02)=0,98²=0,9604
p≈96%