Question

Y^3-2y^+3y-6=0 РЕШИТЕ

Answer 1

$y^3-2y^2+3y-6=0 \\ y=б1;б2;б3;б6 \\ y(1)=1-2+3-6 \neq 0 \\ y(-1)=-1-2-3-6 \neq 0 \\ y(2) = 8-8+6-6=0 \\ \frac{y^3-2y^2+3y-6}{y-2} = y^2+3 \\ (y^2+3)(y-2)=0 \\ y^2+3 \neq 0 ; y^2 \geq 0 \\ y-2=0 ; y=2$

Answer 2

Y^3-2y^2+3y-6=0
(y^3-2y^2)+(3y-6)=0
y^2(y-2) +3(y-2)=0
(y-2)(y^2+3)=0
y-2=0      y^2+3=0
y=2         y^2=-3 - корней нет
Ответ:2