<em>((x²-3x)/(x+2))'=((2x-3)*(x+2)-1*(x²-3x))/(x+2)²=(2x²+</em><u><em>4x</em></u><em>-</em><u><em>3x</em></u><em>-6-x²+</em><u><em>3x</em></u><em>)/(x+2)²=</em>
<em>(x²+</em><u><em>4x</em></u><em>-6)/(x+2)²</em>
<em>воспользовался формулой (u/v)'=(u'v-uv')/v²</em>
7sin²x+7cos²x = 7 ( В формулки заглядывать надо)
7-5+2
<span>-x + 1 + 2(x - 1) = -2(-2 - x) + 2
-x + 1 + 2x - 2 = 4 +2x + 2
x - 1 = 2x + 6
x = -7
</span>
1) f'(x) = 3
2) f'(x) = 8x - 6
3) f'(x) = 6(4x + 3x)^5 * (4x + 3x)' = 6(4x + 3x)^5 * 7 = 42(4x + 3x)^5
4) f'(x) = 2x + ((5')(x - 2) - (x - 2)'5)/(x - 2)^2 = 2x - 5/(x - 2)^2
5) f'(x) = 6x^2 + 1/x^2
6) f'(x) = (e^x)'(sinx) + (sinx)'(e^x) = e^x(sinx + cosx)
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