Эти числа: 210, 211, 212, 213, 214, 215.
Попробую объяснить: разность этих чисел соответственно равна d=1.
по формуле суммы арифметической прогрессии: S=((2а+d(n-1))\(2))*n,
где n - количество чисел
а - первое число
подставляя все в формулу: 1275=((2а+1(6-1))\(2))*6,
из этого а=210. Соответственно последующие числа равны 211, 212, ...
Как-то так)
-10<7x-11<+10
-10+11<7x<+10+11
1<7x<21
1/7<x<3 x∈(1/7;3). В этом множестве два целых числа: 1 и 2.
0,5x-5y+x = 3
0,5 - 5y = -70
1,5x -5y=3
-5y=-70,5
y=14,1
1,5x-5×14,1=3
1,5x=73,5
x=49
Ответ : (49; 14,1)
Так как
, то по теореме Виета
![x_1+x_2=p~~\Rightarrow~~ x_1=p-x_2](https://tex.z-dn.net/?f=x_1%2Bx_2%3Dp~~%5CRightarrow~~+x_1%3Dp-x_2)
![x_1x_2=-10~~\Rightarrow~~~ (p-x_2)x_2=-10](https://tex.z-dn.net/?f=x_1x_2%3D-10~~%5CRightarrow~~~+%28p-x_2%29x_2%3D-10)
И решим уравнение
в целых числах.
Делители числа 10: 1, 2, 5, 10.
![\displaystyle \left \{ {{p-x_2=1} \atop {x_2=-10}} \right.~~\Leftrightarrow~~~\left \{ {{p=-9} \atop {x_2=-10}} \right.\\ \\ \left \{ {{p-x_2=-10} \atop {x_2=1}} \right.~~\Rightarrow~~~\left \{ {{p=-9} \atop {x_2=1}} \right.\\ \\ \left \{ {{p-x_2=-1} \atop {x_2=10}} \right.~~\Rightarrow~~\left \{ {{p=9} \atop {x_2=10}} \right.\\ \left \{ {{p-x_2=10} \atop {x_2=-1}} \right.~~\Rightarrow~~\left \{ {{p=9} \atop {x_2=-1}} \right.](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D1%7D+%5Catop+%7Bx_2%3D-10%7D%7D+%5Cright.~~%5CLeftrightarrow~~~%5Cleft+%5C%7B+%7B%7Bp%3D-9%7D+%5Catop+%7Bx_2%3D-10%7D%7D+%5Cright.%5C%5C+%5C%5C+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D-10%7D+%5Catop+%7Bx_2%3D1%7D%7D+%5Cright.~~%5CRightarrow~~~%5Cleft+%5C%7B+%7B%7Bp%3D-9%7D+%5Catop+%7Bx_2%3D1%7D%7D+%5Cright.%5C%5C+%5C%5C+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D-1%7D+%5Catop+%7Bx_2%3D10%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D9%7D+%5Catop+%7Bx_2%3D10%7D%7D+%5Cright.%5C%5C+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D10%7D+%5Catop+%7Bx_2%3D-1%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D9%7D+%5Catop+%7Bx_2%3D-1%7D%7D+%5Cright.)
![\displaystyle \left \{ {{p-x_2=2} \atop {x_2=-5}} \right.~~\Rightarrow~~\left \{ {{p=-3} \atop {x_2=-5}} \right.\\ \\\left \{ {{p-x_2=-5} \atop {x_2=2}} \right.~~\Rightarrow~~\left \{ {{p=-3} \atop {x_2=2}} \right.\\ \\ \left \{ {{p-x_2=-2} \atop {x_2=5}} \right.~~\Rightarrow~~\left \{ {{p=3} \atop {x_2=5}} \right.\\ \\ \left \{ {{p-x_2=5} \atop {x_2=-2}} \right.~~\Rightarrow~~\left \{ {{p=3} \atop {x_2=-2}} \right.](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D2%7D+%5Catop+%7Bx_2%3D-5%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D-3%7D+%5Catop+%7Bx_2%3D-5%7D%7D+%5Cright.%5C%5C+%5C%5C%5Cleft+%5C%7B+%7B%7Bp-x_2%3D-5%7D+%5Catop+%7Bx_2%3D2%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D-3%7D+%5Catop+%7Bx_2%3D2%7D%7D+%5Cright.%5C%5C+%5C%5C+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D-2%7D+%5Catop+%7Bx_2%3D5%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D3%7D+%5Catop+%7Bx_2%3D5%7D%7D+%5Cright.%5C%5C+%5C%5C+%5Cleft+%5C%7B+%7B%7Bp-x_2%3D5%7D+%5Catop+%7Bx_2%3D-2%7D%7D+%5Cright.~~%5CRightarrow~~%5Cleft+%5C%7B+%7B%7Bp%3D3%7D+%5Catop+%7Bx_2%3D-2%7D%7D+%5Cright.)
Ответ: ± 3; ± 9.
(у+7)²-14у=у²+14у+49-14у=у²+49.