<span>9x^2-10a^3+6ax-15a^2x = (</span><span>9x^2+6ax) - (15a^2x</span><span>+10a^3) = 3х(3х+2а) - 5</span><span>a^2(</span>3х+2а) = (3х+2а)*(3х-5a^2)
(2a-b)^3-(2a+b)^3 = 8a^3-12a^2b+6ab^2-<span>b^3 - </span> 8a^3-12a^2b-6ab^2-b^3 = -24a^2b - 2b^3 = -2b*(12a^2+<span>b^</span>2)
2log3 6-log3 12=log3 ((6^2)/12)=log3 3=1
Числитель
sin(a-b) + sin b*cos a = sin a*cos b - cos a*sin b + sin b*cos a = sin a*cos b
Получается
sin a*cos b / (sin a/cos b) = sin a*cos b*cos b/sin a = cos^2 b
<span> 2x+1/x наверно так,если не ошибаюсь:)</span>