cos2x=1-2sin^2*x заменим
(1-sin^2*x)+2sinx+2=0
-2sin^2*x+2sinx+3=0
sinx=t
-2t^2+2t+3=0
пример точно правильный?
3x^3+4x-1=y
y'=9x^2+4
y'(3)=85
-3/x^2+1/sqrt(x)-e^x
12(3x-5)^3
3cosxcos2x-3sin2xsinx=3cos3x
(3x^2(x^2+5)-x^3(2x))/(x^2+5)^2=(3x^4-2x^4+15x^2)/(x^2+5)^2=x^2(x^2+15)/(x^2+5)^2
y'=-sin3x*3
y'(П/6)=-3sinП/2=-3
y'=4x^3-6x^2 y'(1/2)=4/8-6/4=1/2-3/2=-1
tgA=-1 A=135 градусов
{<span>2х+5у=8 /х3
</span>{-3х+2у=7 /х2
<span>{6х+15у=24
</span><span>{-6х+4у=14
</span>19у=38
у=2
2х+10=8
2х=-2
х=-1