X² + x = 0
x(x + 1) = 0
x=0; x + 1 = 0
x = -1
Ответ: -1 и 0.
-4х²=-25
х²=-25:(-4)
х²=(5/2)²
х=5/2
х=-5/2
Tgx=0,4 ctgx=2,5
ctgy=-3 tgy=-1/3
tg(x+y)=(tgx+tgy)/(1-tgxtgy)=(4/10-1/3)/(1+1/3*4/10)=(1/15)/(17/15)=1/17
ctg(x-y)=(ctgxctgy+1)/(ctgy-ctgx)=(5/2*(-3)+1)/(-3-5/2)=(-13/2):(-11/2)=13/11
0.49b^2-25=(0,7b-5)*(0,7b+5)
25-0,16y^2=(5-0,4y)*(5+0,4y)
8-x^6=(2-x^2)*(4+2x^2+x^4)
-72xy^2+2xz^2=-2x(6y-z)*(6y+z)