замена: y^2=a. получаем: 2a^2-15a-27=0; D=(-15)^2-4*2*(-27)=225+216=441; a1=(15-21)/4, a2=(15+21)/4. a1= -6/4= -3/2. a2=9. y^2= -3/2( корней нет). y^2=9, y1= -3, y2=3. Ответ: y1= -3, y2=3.
V(t) = 0 , t - ?
v(t) = s ' (t) = (2t^2 - 6t + 7) ' = 4t - 6
4t - 6 = 0
4t = 6
t = 6/4 = 3/2 = 1,5
1) (х² -7у³)² +(х² +7у³)² =
= х⁴ - 14х²у³ + 49у⁶ + х⁴ + 14х²у³ + 49у⁶ =
= 2х⁴ + 98у⁶
2) (5a³ - 4b)² +(4b +5a³)² =
= 25a⁶ - 40a³b + 16b² + 16b² + 40a³b + 25a⁶ =
= 50a⁶ + 32b²
<span>a)a^5*a^3 =a^(5+3)=a^8
б) a^8:a^6 =a^(8-6)=a^2
в) (a^2)^4=a^(2*4)=a^8
г) (ab)^6 =a^6b^6
д) (a/b)^3-a^3/b^3</span>