X^2-y=8
y+x=-2
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x^2-y=8
x=-2-y
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(-2-y)^2-y=8
x=-2-y
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4+4y+y^2-y=8
x=-2-y
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y^2+3y-4=0
x=-2-y
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y1=-4; y2=1
x=-2-y
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y1=-4; y2=1
x1=2; x2=-3
ответ: (2; -4) (-3; 1)
Как то так. Я тоже себе так сделаю.
(х+2)(х-2)(х^2+4)-(4+х^2)^2=(х^2-4)(х^2+4)-(16+8х^2+х^4)=х^4-16-16-8х^2-х^4=-8х^2-32= -8(х^2+4)
Если х=1/2=0,5, то -8(х^2+4)=-8(0,5^2+4) =-8(0,25+4) =-8*4,25=-34
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