1) Вверх, т.к к<em>оэффициент при х(в квадрате) положительный</em>
(x-4)(x+2)2
4-x=3x
2+x=4x
3x-4x=1x
Ответ:1x
1)сosx<0⇒x∈(π/2+2πn,3π/2+2πn)
-cosx=cosx-2sinx
2sinx-2cosx=0/cosx
2tgx-2=0
tgx=1
x=π/4+πn +x∈(π/2+2πn,3π/2+2πn)
х=5π/4+2πn,n∈z
2)cosx≥0⇒x∈[-π/2+2πn;π/2+2πn,n∈z]
cosx=cosx-2sinx
sinx=0
x=πn +x∈[-π/2+2πn;π/2+2πn,n∈z]
x=2πn,n∈z
V 675 = V ( 25•9•3 ) = 15 V 3
7 V 507 = 7 V ( 169•3 ) = 91 V 3
3,4 V 1875 = 3,4 V ( 625•3 ) = 85 V 3
V 30000 = V ( 10000•3 ) = 100 V 3
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15 V 3 - 91 V 3 - 85 V 3 + 100 V 3 = 115 V 3 - 176 V 3 = - 61 V 3