(1/2)√12+(1/3)√27+(1/4)√48=(1/2)√(4·3)+(1/3)√(9·3)+(1/4)√(16·3)=
=(1/2)·2√(3)+(1/3)·3√(3)+(1/4)·4√(3)=3√(<span>3)
</span>[(√64)·25]/<span>√25=8</span>·25/5=40
Разделить нужно на старшую степень, на икс в кубе :
![lim \frac{25 - 2 + \frac{3}{ {x}^{3} } }{ \frac{6}{ {x}^{3} } + 5 } = \frac{25 - 2}{5} = \frac{23}{5}](https://tex.z-dn.net/?f=lim+%5Cfrac%7B25+-+2+%2B++%5Cfrac%7B3%7D%7B+%7Bx%7D%5E%7B3%7D+%7D+%7D%7B+%5Cfrac%7B6%7D%7B+%7Bx%7D%5E%7B3%7D++%7D+%2B+5+%7D++%3D++%5Cfrac%7B25+-+2%7D%7B5%7D++%3D++%5Cfrac%7B23%7D%7B5%7D+)
2x^4 - 9x^2 + 4 = 0
x^2 = t
2t^2 - 9t + 4 = 0
D = 81 - 4*4*2 = 49 =7^2
t1 = ( 9 +7)/4 = 4;
t2 = ( 9 - 7)/4 = 2/4 = 1/2
x^2 = 4
x = ± 2
x^2 = 1/2
x = ± √2/2