А-3в > 2а-в
9-3×(-5) и 2×9-(-5)
9+15 и 18+5
24 > 23
AC=(5-3; 12-(-1))=(2;13)
BC=(5-(-1); 12 -(-3))=(6; 15)
<span>f(x)=2x^3-3x^2-12x+1
</span>f⁾(x)=(2x^3-3x^2-12x+1)⁾ =2*3*x²-3*2*x-12*1+0=6x²-6x-12
6x²-6x-12=0 сократим на 6
x²-x-2=0
D=1+8=9
x₁=(1+3)/2=2
x₂=(1-3)/2=-1
(6xy-18x)-(5y+15)=6x(y-3)-5(y-3)=(y-3)(6x-5)