<span>а) 5a(b+c)-10(b+c)= (b+c)*(5a-10)</span>
<span>б) 2a-ac+2b-cb= 2(a+b)-c(a+b)=(a+b)*(2-c) </span>
a)
(5a-10)(b+c)
b)
a(2-c)+b(2-c)=(a+b)(2-c)
4x^2+8x-x-2<1-4x
4x^2+11x-3<0
D=121+48=169
x1=-11-13/8=-24/8=-4
x2=-11+13/8=1/4