-0,4(6х+3)=0,3(9х-38) -2,4х-1,2=2,7х-11,4 -2,4х-2,7х=-11,4+1,2 -5,1х=-10,2 х=-10,2:(-5,11) х=-102:(-51) х=2 Ответ:2.
![\frac{a^2b}{(k-a)} = 4a- ab \\ \\ k-a= \frac{a^2b}{a(4-b) } \\ \\ k-a= \frac{ab}{4-b} \\ \\ k= \frac{ab}{4-b} +a \\ \\](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E2b%7D%7B%28k-a%29%7D+%3D+4a-+ab+%5C%5C+%5C%5C+k-a%3D+%5Cfrac%7Ba%5E2b%7D%7Ba%284-b%29+%7D+%5C%5C+%5C%5C+k-a%3D+%5Cfrac%7Bab%7D%7B4-b%7D+%5C%5C+%5C%5C+k%3D+%5Cfrac%7Bab%7D%7B4-b%7D+%2Ba+%5C%5C++%5C%5C+)
Можно привести к общему знаменателю:
![k= \frac{ab+a(4-b) }{4-b} \\ \\ k= \frac{ab+4a-ab}{4-b} \\ \\ k= \frac{4a}{4-b}](https://tex.z-dn.net/?f=k%3D+%5Cfrac%7Bab%2Ba%284-b%29+%7D%7B4-b%7D++%5C%5C++%5C%5C+%0Ak%3D++%5Cfrac%7Bab%2B4a-ab%7D%7B4-b%7D++%5C%5C++%5C%5C+%0Ak%3D++%5Cfrac%7B4a%7D%7B4-b%7D+)
2x²sinx-8sinx+4=x²;
x²(2sinx-1)-4(2sinx-1)=0;
(x²-4)(2sinx-1)=0;
x²-4=0;
x=4;
x=-4;
2sinx-1=0;
sinx=1/2;
x=(-1)ⁿ·π/6+nπ;n∈Z