Question

Решите уравнение (х-8)^2-(х-4)(х+4)=0;(4х-5)(4х+5)-(4х-1)^2=9-2х

Answer 1

(x-8)ˇ2-(x-4)(x+4)=0
xˇ2-16x+64 -xˇ2+16=0
-16x=-80,
x=5

(4x-5)(4x+5)-(4x-1)ˇ2=9-2x
16xˇ2-25-16xˇ2+8x-1=9-2x
8x-26=9-2x
10x=35,x=3,5