1) 8a-3b+5a=13a-3b
2)6a-2b-5a-3b=a-5b
3)4x+2-x-1=3x+1
<span>Т.е. сумму арифметической прогрессии с а1=2, аn=102 и количеством 102-1=101. Сумма равна (2+102)/2*101=5252.</span>
<span>√6 *√10 *√15 = √(6*10*15) = √900 = 30</span>
1) log₈14 · log₁₄15 ·log₁₅16 = log₈16 = 4/3 log₂2 = 4/3; 2) log₇5 · log₅4 · log₃₂7 = 2/5 · log₇5 · log₅2 · log₂7 = 2/5 log₇7 = 2/5; 3) log₂10 log₁₀11 log₁₁128 = log₂128 = 7· log₂2 = 7; 4) log₁₀₀₀9 · log₃10 = 2/3 · log₁₀3 · log₃10 = 2/3; 5) log₁₂₈81 · log₃2 = 4/7 log₂3 · log₃2 = 4/7; 6) log₈5 · log₁₂₅16 = 4/9 · log₂5 · log₅2 = 4/9
D=196-180=4²
х₁=10/2=5
х₂=18/2=9
Ответ: (х-5)(х-9)