1.
a) t(t+x)+11(t+x)=(t+x)(t+11)
b) 2m²(4-m)-(4-m)=
=(4-m)(2m²-1)
2.
18k²-18k+7y-7ky= =18k(k-1)+7y(1-k)= =18k(k-1)-7y(k-1)=
=(k-1)(18k-7y)=
=(1/9-1)(18/9-14/7)=(1/9-9/9)*
*2-2=0
3. (0.7*2.7-1.4*0.7)+(0.3*2.7-1.4*0.3)=0.7(2.7-1.4)+0.3(2.7-1.4)=(2.7-1.4)(0.7+0.3)=1.3*1=1.3
4M + [ ( 1 - 6M^2 ) / M ] = ( 4M^2 + 1 - 6M^2 ) / M = ( 1 - 2M^2 ) /M
M = 2
( 1 - 8 ) / 2 = ( - 7 ) / 2 = ( - 3,5 )
Ответ:3π/2+3πn,n∈z
Объяснение: cosx/3·cos2x/3+sin2x/3·sinx/3-1/2cosx/3=0
cos(2x/3-x/3)-1/2cosx/3=0
cosx/3-1/2cosx/3=0
1/2c0sx/3=0
cosx/3=0
x/3=π/2+πn,n∈z⇒ x=3π/2+3πn,n∈z
(у тебя неточное условие,обрати внимание где знак =?)
3х⁹ : х⁵ = 3х⁹⁻⁵ = 3х⁴
(3х⁵)² = 3²х⁵*² = 9х¹⁰